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Question

Two bodies are projected vertically upwards from one point with the same initial velocities v0 m/s. The second body is thrown τ s after the first. The two bodies meet after time
  1. v0gτ2
  2. v0g+τ
  3. v0g+τ2
  4. v02gτ


Solution

The correct option is C v0g+τ2
Height of first body after time t,h1=v0t12gt2
Height of the second body after time (tτ),
h2=v0(tτ)12g(tτ)2
If they meet after time t,  h1=h2
t=v0g+τ2
The correct option is (c).

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