Question

# Two boys A and B start at the same time to ride from Delhi to Meerut , $$60km$$ away.A travels $$4$$ hour slower than B.B reaches Meerut and at once turns back meeting A $$12$$,km from Meerut Find A's speed ?

A
6 km/hr
B
4 km/hr
C
8 km/hr
D
10 km/hr

Solution

## The correct option is C $$8$$ km/hrLet the speed of B$$=x$$ km/hspeed of A$$=(x-4)$$km/hDistance travelled by A$$=60-12=48$$kmDistance travelled by B$$=60+12=72$$kmTime will be same in both cases$$T_1=\dfrac{48}{x-4}$$$$T_2=\dfrac{72}{x}$$So$$\Rightarrow \dfrac{48}{x-4}=\dfrac{72}{x}$$$$48x=72x-288$$$$48x-72x=-288$$$$-24x=-288$$$$x=\dfrac{288}{24}$$$$x=12$$So speed of A$$=x-4$$$$=12-4$$$$=8$$ km/h Answer.Mathematics

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