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Question

Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is

A
av2+v21
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B
a2v2v21
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C
a(vv1)
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D
a(v+v1)
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Solution

The correct option is C a2v2v21
If boy A catches boy B in time t,
(vt)2=(v1t)2+a2
t2=a2v2v21
t=av2v21

504096_466846_ans_f93ad6aaac1c4d87a1199f8f4562ac9b.png

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