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Question

# Two capacitors of 400 μF and 600 μF in parallel are connected to a battery of 100 V. Find the ratio of charge stored in 400 μF to charge stored in 600 μF.

A
23
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B
13
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C
12
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D
32
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Solution

## The correct option is A 23 The capacitors are in parallel, which implies that the potential difference across both the capacitors will be 100 V. Now the charge on 400 μF: Q1=(400 μF)×(100 V)=40000 μC And the charge on 600 μF: Q2=(600 μF)×(100 V)=60000 μC So, the ratio of the cahrges: Q1Q2=4000060000=23 Hence, option (a) is the correct answer. Key concept: Charge on capacitors in parallel combination in a circuit.

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