Question

Two capacitors of capacities 3$\mu$F and 6$\mu F$ are connected in series and connected to 120V. The potential differences across 3$\mu$F is $V_0$ and the charge here is $q_0$. We have :

A)$q_0=40\mu C$ B) $V_0=60V$

C)$V_0=80V$ D)$q_0=240\mu C$

• A. A, C are correct
• B. A, B are correct
• C. B, D are correct
• D. C, D are correct

Answer 1

The correct option is D C, D are correct

When capacitor are connected is series charge present on capacitor is same.
Now,
$q_0=CV=240\times {10}^{-6}$
We know,
$V_0=\frac{q_0}{C}$
$V_0=\frac{240\times {10}^{-6}}{3\times {10}^{-6}}$
$V_0=80V$