Two cars $A$ and $B$ moving on two straight horizontal tracks inclined at an angle of $60^{o}$ are heading towards the crossing. Initially their positions are as shown in figure. Both cars have same speed. Minimum separation between them during the motion will be.

10 k m

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5 \sqrt{3} k m

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5 k m

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\frac{20}{\sqrt{3}} k m

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Solution

The correct option is B $5 \sqrt{3} k m$
$A C D$ is equilateral $Δ$
$C D = 40 k m$
$= B C = 10 k m$
$∠ D C A = 60^{0}$
$∴ d = 10 sin 60^{0}$
$= 10 \times \frac{\sqrt{3}}{2} = 5 \sqrt{3} k m$
$∴ d = 5 \sqrt{3} k m$
hence,
option $(B)$ is correct answer.

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Two cars A and B moving on two straight horizontal tracks inclined at an angle of 60o are heading towards the crossing. Initially their positions are as shown in figure. Both cars have same speed. Minimum separation between them during the motion will be.

The correct option is B 5√3 kmACD is equilateral Δ CD=40km=BC=10km∠DCA=600∴d=10sin600=10×√32=5√3km∴d=5√3kmhence,option (B) is correct answer.

Two cars $A$ and $B$ moving on two straight horizontal tracks inclined at an angle of $60^{o}$ are heading towards the crossing. Initially their positions are as shown in figure. Both cars have same speed. Minimum separation between them during the motion will be.

The correct option is B $5 \sqrt{3} k m$
$A C D$ is equilateral $Δ$
$C D = 40 k m$
$= B C = 10 k m$
$∠ D C A = 60^{0}$
$∴ d = 10 sin 60^{0}$
$= 10 \times \frac{\sqrt{3}}{2} = 5 \sqrt{3} k m$
$∴ d = 5 \sqrt{3} k m$
hence,
option $(B)$ is correct answer.