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Question

Two cars intially at 20 km from the square are approaching towards it. One at 60 km/h and another at 80 km/h. Minimum separation between the cars is [in km] (Write until two digits after the decimal point.)


Solution


Place the frame of reference on B,
VAB=VAVB=80^j60^i
then the path of A is as shown by the dotted line in the figure.
Angle made by path is 37 degrees. 
The perpendicular x becomes the shortest distance between A and B.
b20=tan 37
b=20×34=15
a=2015=5
x=a cos 37=5×45=4

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