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Question

Two charged particles are placed at a distance $$1.0cm$$ apart. What is the minimum possible magnitude of the electric force acting on each charge?


Solution

Minimum charge of a body is the charge of an electron
Wo, $$q=1.6\times 10^{-19}C$$
$$\chi =1cm=1\times 10^{-2}$$cm
So, $$F=\dfrac{kq_1q_2}{r^2}=\dfrac{9\times 10^9\times 1.6\times 1.6\times 10^{-19}\times 10^{-19}}{10^{-2}\times 10^{-2}}=23.04\times 10^{-38+9+2+2}=23.04\times 10^{-25}=2.3\times 10^{-24}$$N.

Physics
NCERT
Standard XII

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