Two charged spheres separated at a distance d exert a force F on each other. If they are immersed in a liquid of dielectric constant 2, then what is the force (if all conditions are same)

\frac{F}{2}

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Solution

The correct option is D. $\frac{F}{2}$ .
The force exerted by the charges is given as follows:
$F = \frac{1}{4 π ϵ_{o}} \frac{q_{1} q_{2}}{r^{2}}$
If the charges are immersed in a liquid, then the force between them is
$F_{n e w} = \frac{1}{K} \frac{1}{4 π ϵ_{o}} \frac{q_{1} q_{2}}{r^{2}}$
Where K is the dielectric constant of the liquid.
Therefore, $F_{n e w} = \frac{F}{K} = \frac{F}{2}$ .

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Two charged spheres separated at a distance d exert a force F on each other. If they are immersed in a liquid of dielectric constant 2, then what is the force (if all conditions are same)

The correct option is D. F2. The force exerted by the charges is given as follows:F=14πϵoq1q2r2If the charges are immersed in a liquid, then the force between them isFnew=1K14πϵoq1q2r2Where K is the dielectric constant of the liquid.Therefore, Fnew=FK=F2.