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Question

Two charges 2.0×106C and 10×106C are placed at a separation of 10 cm. Where should a third charge be placed such that it experiences no net force due to these charges?

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Solution

If both are positive charge then the third charge should be placed on the line joining two charge.
F1=F2
2qr2=1q(10r)2
r2=2(10r)2
r2=200+2r240r
r240r+200=0
r=[40±(1600800)]2
r=[40(1600800)]2 Since the point should be in between
r=20102
r=5.86cm

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