Question

Two charges $+3.2\times {10}^{-19}C$ and $-3.2\times {10}^{-19}C$ placed at $2.4\stackrel{o}{A}$ apart to form an eletric dipole. It is placed in a uniform electric field of intensity $4\times {10}^5\text{volt/m}$. The electric dipole moment is

• A. $15.36\times {10}^{-29}\text{Coulomb}\times \text{m}$
• B. $15.36\times {10}^{-19}\text{Coulomb}\times \text{m}$
• C. $7.68\times {10}^{-29}\text{Coulomb}\times \text{m}$
• D. $7.68\times {10}^{-19}\text{Coulomb}\times \text{m}$

Answer 1

The correct option is C $7.68\times {10}^{-29}\text{Coulomb}\times \text{m}$

Dipole moment of a dipole is $p=q\left(r\right)$
Where $q$ is charge of the particle.
$r$ is separation between the particles

$p=3.2\times {10}^{-19}\times (2.4\times {10}^{-10})=7.68\times {10}^{-29}C-m$