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Question

Two children are at opposite ends of an iron pipe. One strikes his end of the iron pipe with a stone. Find the ratio of times taken by the sound wave in air and in iron to reach the other child. Given, velocity of sound in air is 344 ms−1 and that in iron is 5130 ms−1.

A
t1t2=14.3
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B
t1t2=11.9
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C
t1t2=14.9
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D
t1t2=10.4
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Solution

The correct option is C t1t2=14.9
Here, the distance travelled by sound waves through air and iron is same which is equal to the thickness (s) of the rod.

For air, jet the speed be v1 and time be t1.

For iron, let the speed be v2 and time be t2.

Now, v1=st1ors=v1t1 ...(1)

Also, v2=st2ors=v2t2 ...(2)

From (1) & (2), we get, v1t1=v2t2

t1t2=5130344=14.9

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