Question

Two chords $AB$ and $CD$ of a circle intersect each other(internally) at $P$.If $AP=4$cm, $PB=6$cm and $CP=2$cm, find $PD$

Answer 1

By the given data $AB$ and $CD$ are the chords intersect at $P$ inside the circle.

$\Rightarrow AP\times PB=CP\times PD$

$\Rightarrow 4\times 6=2\times PD$

$\therefore PD=\frac{24}{2}=12$cm