CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Two circles of radii 10 cm and 8 cm intersect at two points and  the length of the common chord is 12 cm. Find the distance between their centres.


Solution


Proof: In circle 'a' OP is radius. PQ is chord, OXPQ
PX=12PQ from centre to chord bisects chord
PQ=12 cm
PX=6 cm
POPX=12OX
106=4 cm
OX=8 cm
Although, you are getting the right ans, here but the method is wrong
OE - OX = XE
10 - 8 cm = 2 cm
XE = 2 cm

2) In circle 'b'
OP is radius
PQ is chord
OXPQPX=12POprovedPX=6 cmprovedPOPX=12OX
8 - 6 = 2 cm
OX=4 cmODOX=XD84=4 cmXD=4 cm

3) OO=(OX+OX)(DX+XE)
=(8+4)-(2+4)
=12-6
=6 cm

1) We cannot say that,OX = 8 cm
Consider ΔOPX
OP is radius

OX has to be calculated using pythagoras theorem.
102=62+OX2
OX2=10036=64
OX=8 cm

2) |||ly in ΔPOX
PO2=PX2+XO282=62+XO2XO2=6436=28XO=28
Distance between centres
 

All India Test Series

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image