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Question

Two complementary angles are in the ratio $$7:8$$. Find the angles


Solution

It is given that two complementary angles are in the ratio $$7:8$$.


Consider $$7x$$ and $$ 8 x $$ as the angles.


We know that, if two angles are complementary, then their sum is $$90^o$$.

Then, $$ 7x + 8x = 90^0 $$

$$\implies$$ $$ 15x = 90^0 $$

$$\implies$$ $$ x = \dfrac{90}{15} = 6^0 $$.


Here, the angles will be:

$$ 7x=7\times 6^o=42^0 $$ and $$8x= 8 \times 6 = 48^0 $$.


Mathematics

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