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Question

# Two completely miscible liquids A and B form an ideal solution. What is the vapour pressure of a solution containing 2 moles of A and 3 moles of B at 300 K? Given: At 300 K, Vapour pressure of pure liquid A (P0A) = 100 torr Vapour pressure of pure liquid B (P0B) = 300 torr

A
200 torr
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B
140 torr
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C
180 torr
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D
None of these
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Solution

## The correct option is D None of theseAccording to Raoult's law, the total vapour pressure of solution is given by P = P0AχA + P0BχB Given, P0A = 100 torr P0B = 300 torr Number of moles of A = 2 Number of moles of B = 3 Total number of moles of A and B =2+3=5 mole fraction of A, χA=moles of Atotal moles=25 similarly mole fraction of B, χB=35 P=100(25) + 300(35) P=220 torr

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