Question

# Two concentric circles are of radii $$6.5cm$$ and $$5.2cm$$. Find the length of the chord of the larger circle which touches the smaller circle

Solution

## $${AP}^{2}={AO}^{2}-{OP}^{2}$$$$\Rightarrow {AP}^{2}={6.5}^{2}-{5.2}^{2}=42.25-27.04=15.21$$$$\Rightarrow AP=\sqrt{15.21}=3.9$$m$$AB=2\times 3.9=7.8$$cmMathematics

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