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Question

Two concentric, thin metallic spheres of radii R1 and R2(R1>R2) bear charges Q1 and Q2 respectively. Then the potential at distance r between R1 and R2 will be (k=14πϵ0)

A
k(Q1+Q2r)
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B
k(Q1r+Q2R2)
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C
k(Q2r+Q1R1)
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D
k(Q1R1+Q2R2)
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Solution

The correct option is C k(Q2r+Q1R1)

Potential due to sphere of radii R2 is V2=kQ2r (as r outside of the sphere)

Potential due to sphere of radii R1 is V1=kQ1R1 (as r inside of the sphere and potential inside metal sphere is constant).

Total potential Vr=V1+V2=kQ1R1+kQ2r=k(Q1R1+Q2r)


249566_202118_ans_8f55240709b8474b991e3f744d5c4a0b.png

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