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Question

Two conducting wires A and B are made of same material. If the length of B is twice that of A and the radius of circular cross-section of A is twice that of B, then their resistances RA and RB are in the ratio __________.

A
2:1
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B
1:2
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C
1:8
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D
1:4
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Solution

The correct option is C 1:8
We know that.
R= ρlA
Thus R l and R 1A
RARB = lAlB×ABAA

RARB = lA2 lA×π r2Bπ r2A

RARB = lA2 lA×π r2Bπ 22r2B

RARB = 12×14 = 18


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