Question

Two containers A and B contain mixture of milk and water such that A contains 40% milk and B contains 22% milk. Some part of mixture in container A is replaced by equal quantity of mixture from container B. How much quantity of the mixture was replaced if final mixture contains 32% milk

Answer 1

REF.Image

So ratio is $8:10=4:5$

So replaced part = $\frac{5}{4+5}=\frac{5}{9}$