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Question

Two cubes have their face painted as either red or blue color. 1st cube has 5 faces red and 1 face blue. The Probability that both the faces show same color on rolling is 12. How many red faces are present on the 2nd cube.
  1. 4
  2. 3
  3. 6
  4. 2


Solution

The correct option is B 3

Suppose x faces of cube 2 is red then 6-x will be blue.

P(RR or BB)= 56×x6+16×(6x)6=12

5x36+(6x)36=12

4x+6=18

x=3

Hence number of red faces is 3.

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