Two cylindrical vessels containing water and mercury have a hole in the wall near the bottom. The relation in velocity of water (v₁) and mercury (v₂) coming out is.

v₁ = v₂

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v₁ = 13.6 v₂

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v₁ = v₂/13.6

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Solution

The correct option is A v₁ = v₂
As clear from the Torricelli's equation, speed of Efflux = $\sqrt{2 g h}$
i.e., it is independent of density of liquid contained.

Therefore both will come out with same velocity.

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Similar questions

Q. Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.
(a) v₁ = v₂
(b) v₁ = 13.6 v₂
(c) v₁ = v₂/13.6
(d)

v_{1} = \sqrt{13.6} v_{2}

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]

Q. Two cylindrical vessels containing water and mercury have a hole in the wall near the bottom. The relation in velocity of water (v₁) and mercury (v₂) coming out is.

Water and mercury are filled in two cylindrical vessels upto same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are $v_{1}$ and $v_{2}$ respectively. Thus

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Two cylindrical vessels containing water and mercury have a hole in the wall near the bottom. The relation in velocity of water (v1) and mercury (v2) coming out is.

The correct option is A v1 = v2As clear from the Torricelli's equation, speed of Efflux = √2gh i.e., it is independent of density of liquid contained. Therefore both will come out with same velocity.

Two cylindrical vessels containing water and mercury have a hole in the wall near the bottom. The relation in velocity of water (v₁) and mercury (v₂) coming out is.

The correct option is A v₁ = v₂
As clear from the Torricelli's equation, speed of Efflux = $\sqrt{2 g h}$
i.e., it is independent of density of liquid contained.

Therefore both will come out with same velocity.