Question

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table.
What is the probability of getting a sum:

Sum	Frequency
2	14
3	30
4	42
5	55
6	72
7	75
8	70
9	53
10	46
11	28
12	15

more than 10?

Answer 1

Two dice are thrown $500$ times. So, the total number of trials are $500$.

Let $E_2$ be the event that sum of two numbers appearing on the uppermost face of two dice be more than $10$., sum $11$ or $12$.

Number of times in which the event happed $=28+15=43$

$\therefore P\left(E_2\right)=\frac{Numberoftrailsinwhichtheeventhapped}{Totalnumberoftrails}$

$=\frac{43}{500}=0.086$