Question
Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:
Sum
Frequency
2
14
3
30
4
43
5
55
6
72
7
75
8
70
9
53
10
46
11
28
12
15
If the dice are thrown once more, what is the probability of getting a sum more than 10?
| Sum | Frequency |
| 2 | 14 |
| 3 | 30 |
| 4 | 43 |
| 5 | 55 |
| 6 | 72 |
| 7 | 75 |
| 8 | 70 |
| 9 | 53 |
| 10 | 46 |
| 11 | 28 |
| 12 | 15 |
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Solution
The correct option is B 0.086
If we rolled dice around 500 times then it can be considered as its expected outcome, hence the probability of obtaining more than 10 as sum (28+15)/500=0.086
If we rolled dice around 500 times then it can be considered as its expected outcome, hence the probability of obtaining more than 10 as sum (28+15)/500=0.086
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