Question

Two dice are thrown simultaneously 500 times. Each time the sum of two numbers appearing on their tops is noted and recorded as given in the following table:

Sum	Frequency
2	14
3	30
4	43
5	55
6	72
7	75
8	70
9	53
10	46
11	28
12	15

If the dice are thrown once more, what is the probability of getting a sum more than 10?

• A. $0.05$
• B. $0.063$
• C. $0.08$
• D. $0.086$

Answer 1

Answer: (D)

$0.086$

If we rolled dice around 500 times then it can be considered as its expected outcome, hence the probability of obtaining more than 10 as sum $(28+15)/500=0.086$