Question

Two dice are thrown simultaneously. Find the probability of getting a multiple of $2$ on one dice and a multiple of $3$ on the other.

• A. $\frac{9}{36}$
• B. $\frac{10}{36}$
• C. $\frac{11}{36}$
• D. $\frac{5}{36}$

Answer 1

Answer: (C)

$\frac{11}{36}$

Total number of possible cases $=36$
Favourable cases of getting multiple of $2$ on one dice and a multiple of $3$ on the other
$=\left\{\right(2,3),(2,6),(3,2),(3,4),(3,6),(4,3),(4,6),(6,2),(6,3),(6,4),(6,6\left)\right\}$
Total number of favourable cases $=11$
P (multiple of $2$ on one dice and a multiple of $3$ on other dice) $=\frac{11}{36}$