Question

Two dice are thrown simultaneously. Find the probability of getting an even number as the sum.

• A. $\frac{1}{6}$
• B. $\frac{1}{2}$
• C. $\frac{5}{6}$
• D. $\frac{1}{3}$

Answer 1

Answer: (B)

$\frac{1}{2}$

Total number of possible cases $=36$
Favourable cases of getting even number as the sum
$=\left\{\right(1,1),(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(4,6),(5,1),(5,3),(5,5),(6,2),(6,4),(6,6\left)\right\}$
Total number of favourable cases $=18$
$P$(getting even number as the sum) $=$ $\frac{18}{36}=\frac{1}{2}$