Question

Two dice are thrown simultaneously. Find the probability of getting the sum as a prime number.

• A. $\frac{15}{36}$
• B. $\frac{5}{6}$
• C. $\frac{14}{37}$
• D. None of these

Answer 1

The correct option is A $\frac{15}{36}$

Total number of possible cases $=36$
Favourable cases of getting sum as a prime number
$=\left\{\right(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2),(3,4),(4,1),(4,3),(5,2),(5,6),(6,1),(6,5\left)\right\}$
Total number of favourable cases $=15$
P (Getting a prime number) = $\frac{15}{36}$