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Question

Two different liquids are flowing in two tubes of equal radius. The ratio of coefficient of viscosity of liquids is 52:49 and the ratio of their densities is 15.6:1, then the ratio of their critical velocities will be:

A
0.068
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B
0.68
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C
6.8
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D
68
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Solution

The correct option is D 0.068

The critical velocity depends on coefficient of viscosity η, density of the liquid ρ, and radius of the tube r as given by:

vc=Kηρr where K is the constant of proportionality
vc1vc2=Kη1ρ1r1Kη2ρ2r2=η1η2×ρ2ρ1×r2r1vc1vc2=5249×115.6×1=0.068


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