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Question

Two drops of same radius are falling through air with steady speed v. If these two drops coalesce and form a big drop, then new terminal speed will be :


A
V
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B
2V
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C
3V
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D
None of these
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Solution

The correct option is D None of these
$$\begin{array}{l}V \\ r\end{array}+\begin{array}{l}V \\ r\end{array} \Rightarrow \begin{array}{l}V^{\prime} \\ R\end{array}$$
$$\dfrac{4}{3} \pi r^{3}+\dfrac{4}{3} \pi r^{3}=\dfrac{4}{3} \pi R^{3}$$
$$V=\dfrac{2 r^{2} g(s-\sigma)}{9 \eta}$$
$$V^{\prime}=2^{2 / 3} V$$
$$V^{\prime}=4^{1 / 3} V$$
Option is (D).

Physics

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