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Question

Two drops of the same radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, the terminal velocity would be

A
10cm/s
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B
2.5cm/s
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C
5(4)1/3cm/s
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D
5(3)1/3cm/s
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Solution

The correct option is D 5(4)1/3cm/s
terminal velocity (V)α r2
=Kr2
Now the volume of each drop =(43πr3)
The volume of coalesced = 2×43πR3
Radius of coalesce drop = (2)13r
Hence, ter,inal velocity of coalesced drop
v1=k[(2)13r]
=(2)23×5
V=(4)13×5

Hence option (C) is correct


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