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Question

Two figures are given
In fig (i) PQ is a tangent to the circle at T,BTA=45andPTB=70. Find ABT.
In fig (ii) O is the centre and PQ is a tangent to circle at R. Calculate STR.
328361.bmp

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Solution

InFigure1BTA=45(Given)PTB=70(Given)ATP=PTB+BTA=45+70=115......(1)ATQ+ATP=180(LinearPairofangles)ATQ=180ATP=180115=65[From(1)]ABT=ATQ=65[Ananglebetweenatangentandachordthroughthepointofcontactisequaltotheangleinthealternatesegment].InFigure2TRQ=30(Given)SRT=90[Angleinasemicircle]NowRST=TRQ=30[Anglesinthealternatesegments]RTS=9030=60

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