Two fishes are $1 m$ apart underwater. The gravitational force between them is $F_{1}$ ,They jump above the surface of water keeping the same distance (i.e $1 m$ ) between them. The new gravitational force between them is $F_{2}$ . The relationship between $F_{1}$ and $F_{2}$ is

F_{1}

F_{2}

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F_{1}

F_{2}

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F_{1} = F_{2}

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F_{1} : F_{2} = 1 : 2

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Solution

The correct option is D $F_{1} = F_{2}$
Answer is C.

The force of gravity between two objects is determined by the mass of each object and the distance between their centers. Objects with a greater amount of mass will exert a greater degree of gravitational pull, but as the distance between two objects increases, the gravitational force between them lessens.
In this case, the distance between the two fishes remains the same both inside and outside the water. So the force between them remains the same both inside and outside the water. That is, $F_{1} = F_{2}$ .

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Two fishes are 1m apart underwater. The gravitational force between them is F1,They jump above the surface of water keeping the same distance (i.e 1m) between them. The new gravitational force between them is F2. The relationship between F1 and F2 is

Two fishes are $1 m$ apart underwater. The gravitational force between them is $F_{1}$ ,They jump above the surface of water keeping the same distance (i.e $1 m$ ) between them. The new gravitational force between them is $F_{2}$ . The relationship between $F_{1}$ and $F_{2}$ is