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Question

Two friends $$A$$ and $$B$$ are $$30$$ km apart and they start simultaneously on motorcycles to meet each other. The speed of $$A$$ is $$3$$ times that of $$B$$. The distance between them decreases at the rate of $$2$$ km per minute. Ten minutes after they start $$A's$$ vehicle breaks down and $$A$$ stops and waits for $$B$$ to arrive. After how much time (in minutes) A started riding, does B meet A ?


A
15
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B
20
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C
25
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D
30
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Solution

The correct option is B $$20$$
Let speed of $$B = V \, km/hr$$
Let speed of $$A = 3V \, km/hr $$ 
Given $$ 4r = 2 \times 60 \, km/hr \Rightarrow V = 30 \, km/hr $$
Distance covered by then after $$10 \, min. = 2 \times 10 = 20 \, km $$
So, remaining distance $$ = (30 - 20) \, km = 10 km $$
Time taken by $$B$$ to cover $$\displaystyle 10 \, km = \frac {10} {30} = 20 \, min $$

Mathematics

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