Question

Two groups consisting of 108 and 156 students participate in sports meet. In how many rooms cfan all these students be accommodated at the minimum, it all the rooms should have equal number of students and no two students in a room should be from different groups ?

Answer 1

The most common multiple of 108&156 is 12.
So in a room can contain 12 students.

There fore;
Rooms required for first group is 108/12=9
Rooms requited by second group is 156/12=13

So,
Total rooms required,
=9+13=22