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Question

Two identical capacitor C1 and C2 are connected in series with a battery. They are fully charged. Now dielectric slab is inserted between the plates of C2. The potential difference across C1 will
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A
Increase
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B
Decrease
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C
Remain same
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D
Depend on internal resistance of the cell
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Solution

The correct option is A Increase
C=QV V=QC
Whenever capacitors are connected in series, the charge accumulated in their plates is common. Hence Q is common.
Initially, the capacitance of both is the same. Vis same for both.
Whenever a dielectric material is inserted in between the plates of a capacitor, its capacitance increases. NowC2>C1
If we look at the above equations, we can note that for Q to remain common for both, and for C2 to increase, V2 has to decrease.
V=V1+V2 here V is the PD of the cell.
Since that doesn't change, and if V2 decreases, V1 has to increase.
The potential difference across C1 will increase.

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