Question

Two identical capacitors $C_1$ and $C_2$ are connected in series with a battery as shown in the figure. They are fully charged. Now dielectric slab is inserted between the plates of $C_2$. The potential difference across $C_1$ will now

• A. increase
• B. decrease
• C. remain same
• D. depend on internal resistance of the cell

Answer 1

The correct option is A increase

We know that voltage is divided in inverse ratio in series combination of capacitor as $V=\frac{Q}{C}$

And, on inserting dielectric slab between the plates of $C_2$ ,its capacitance will be increased as $C=\frac{k{ϵ}_{0}A}{d}$

So, on inserting dielectric slab between the plates of $C_2$,the potential difference across $C_2$ decreases and the potential difference across $C_1$ will now increases.

Therefore, A is correct option.