Two identical parallel plate capacitors are joined in series to $100 V$ battery. Now a dielectric with $K = 4$ is introduced between the plates of second capacitor. The potential difference on capacitors now becomes

60 V, 40 V

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70 V, 30 V

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75 V, 25 V

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80 V, 20 V

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Solution

The correct option is C $80 V, 20 V$
Introducing a dielectric increases the capacitance by $K$ .
Now, charge on both the capacitors is same $\Rightarrow C V_{1} = 4 C V_{2}$
Also, $V_{1} + V_{2} = 100 V \Rightarrow 5 V_{2} = 100 \Rightarrow V_{2} = 20 V$
$V_{1} = 100 - 20 V = 80 V$
Potential across capacitors $= 80 V, 20 V$

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