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Question

Two identical pith balls are charged by rubbing against each other.  they are suspended from a horizontal rod through two strings of length 20 cm each, the separation between the suspension points being 5 cm. In equilibrium, the sepaation between the balls is 3 cm. Find the mass of each ball and the tension in the stirngs. The charge on each ball ahs a magnitude 2.0×108 C.
 


Solution

Tcosθ=mgTsinθ=F

sinθ=120
cosθ=1(120)2
From equation (i) and (ii) 
tanθ=Fmgm=Fgtanθorm=9×109×(2×108)29×104×.98×tanθ=8.2gT=Fsinθ=9×109×(2×108)29×104×120T=8.2×102N
 

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