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Question

Two identical spring of constant K are connected in series and parallel as shown in figure. A mass m is suspended from them. The ratio of their frequencies of vertical oscillations will be

 



A

2:1

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B

1:1

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C

1:2

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D

4:1

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Solution

The correct option is C

1:2


n = 12πkmnSnP=kSkPnsnp=(k2)2k=12 


Physics

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