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Standard XII

Chemistry

Kinetic Theory of Gases

Two liquids a...

Question

Two liquids at temperature $60^{o}$ C and $20^{o}$ C respectively have masses in the ratio $3 : 4$ and their specific heats in the ratio $4 : 5$ . If the two liquids are mixed, the resultant temperature is.

70^{o}

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50^{o}

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40^{o}

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35^{o}

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Solution

The correct option is D $35^{o}$ C
Ratio of mass = $\frac{3}{4}$
Ratio of specific heat = $\frac{4}{5}$
Let final temperature be $T$
$m_{1} S_{1} (60 - T) = m_{2} S_{2} (T - 20) \Rightarrow (60 - T) = \frac{m_{2} S_{2}}{m_{1} S_{1}} (T - 20) \Rightarrow (60 - T) = \frac{4}{3} \times \frac{5}{4} (T - 20) \Rightarrow 3 (60 - T) = 5 (T - 20) \Rightarrow 180 - 3 T = 5 T - 100 \Rightarrow 280 = 8 T \Rightarrow T = 35 ℃$

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Two liquids at temperature 60oC and 20oC respectively have masses in the ratio 3:4 and their specific heats in the ratio 4:5. If the two liquids are mixed, the resultant temperature is.

The correct option is D 35oCRatio of mass = 34Ratio of specific heat = 45Let final temperature be Tm1S1(60−T)=m2S2(T−20)⇒(60−T)=m2S2m1S1(T−20)⇒(60−T)=43×54(T−20)⇒3(60−T)=5(T−20)⇒180−3T=5T−100⇒280=8T⇒T=35℃

Two liquids at temperature $60^{o}$ C and $20^{o}$ C respectively have masses in the ratio $3 : 4$ and their specific heats in the ratio $4 : 5$ . If the two liquids are mixed, the resultant temperature is.