Question

# Two-litre of N2 at 0oC and 5 atm pressure is expanded isothermally against a constant external pressure of 1 atm until the pressure of gas reaches 1 atm, work of expansion is: [assuming gas to be ideal]

A
710.10 J
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B
610.10 J
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C
810.10 J
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D
None
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Solution

## The correct option is C 810.10 JUsing ideal gas equation,PV=nRTFor isothermal condition,PV=Constant∴P1V1=P2V2.....(1)Given:-P1=5atmP2=1atmV1=2LV2=V(say)=?Now from eqn(1), we have5×2=1×V⇒V=10L∴V2=10LAs we know that, in an irreversible isothermal expansion, the work t=done is given as-W=−Pext.ΔVGiven that Pext.=1atm∴W=−1(10−2)=−8L−atm=−810.64J≈−810.10JHere −ve sign indicates that the gas is expanding.Hence the work done of expansion is 810.10J.Hence, the correct option is C

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