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Question

Two long conductors separated by a distance d carry currents i1 and i2 in the same direction. They exert a force F on each other. Now the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of the force between them is
  1. F3
  2. 2F3
  3. 2F
  4. F3


Solution

The correct option is B 2F3
Initially F=μ02πi1i2d  

Now i1 is doubled,reversed  and d is tripled. New Force is 
F=μ02π(2i1)i23d 
FF=23
F=2F3

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