Question

Two long parallel wires are separated by a distance of $2.50cm$.The force per unit length that each wire exerts on the other is $4.00\times {10}^{-5}N/m$, and the wires repel each other. The current in one wire is $0.600A$. What is the current in the second wire?

• A. $8.33A$
  
• B. $9.56A$
  
• C. $5.45A$
  
• D. $6.88A$
  

Answer 1

The correct option is A $8.33A$

$\frac{F}{l}=\left(\frac{{\mu }_o}{2\pi }\right)\frac{i_1{i}_2}{r}$

$4\times {10}^{-5}=\frac{(2\times {10}^{-7})\left(0.6\right)i_2}{2.5\times {10}^{-2}}$

$\therefore i_2=8.33A$