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Question

Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a friction less pulley fixed at the corner of a table as shown. The coefficient of static friction of A with table is 0.2. The minimum mass of C that may be placed on A to prevent it from moving is
293151_ef079d507f4c4746bbfdefa8250e0bc6.png

A
15 kg
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B
10 kg
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C
5 kg
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D
12 kg
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Solution

The correct option is A 15 kg
Since for B
Mg=T
=5g=T
For AC
(10+m)gμ=T
5g=(10+m)gμ
5=(10+m)(0.2)
5=2+0.2m
3=0.2m
m=15Kg

976022_293151_ans_2717d74b5b4b4f7581277a5958296807.png

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