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Standard XII

Physics

Optical Path Length

Two masses ...

Question

Two masses $m_{1}$ and $m_{2}$ are connected by a light string passing over a smooth pulley. When set free $m_{1}$ moves downward by 2 m in 2s. The ratio $m_{1} / m_{2}$ is:

9/7

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11/9

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13/11

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15/13

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Solution

The correct option is B 11/9
$\frac{1}{2} a_{m_{1}} t^{2} = s$

$\frac{1}{2} a_{m_{1}} * 4 = 2$

$a_{m_{1}} = 1 \frac{m}{s^{2}}$

$\frac{[m_{1} g - m_{2} g]}{m_{1} + m_{2}} = a_{m_{1}}$

$\frac{\frac{m_{1}}{m_{2}} g - g}{\frac{m_{1}}{m_{2}} + 1} = 1$

$x g - g = x + 1$

$9 x = 11$

$x = \frac{11}{9}$

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