Question

Two masses, m1 and m2 were moving in opposite direction with speeds of 20 m/s and 10 m/s respectively. They collide and m1 moves with 15 m/s after collision in its same direction as of before collision. What is the speed and direction of the second particle after collision, if the coefficient of restitution is 2/3?

A
35 m/s in same direction as of first particle
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B
20 m/s in same direction as of first particle
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C
35 m/s in opposite direction as of first particle
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D
20 m/s in opposite direction as of first particle
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Solution

The correct option is A 35 m/s in same direction as of first particle The coefficient of restitution is given by, e=separation speedapproach speed=v2−v1u1−u2=23 ⇒v2−1520−(−10)=23 ⇒3v2−45=60 ∴v2=35 m/s As v2 comes out to be positive, so both m1 and m2 will travel in the same direction after collision. Hence, option (A) is the correct answer.

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