    Question

# Two metallic spheres of radii 1 cm and 3 cm are given charges of −1×10−2C and 5×10−2C respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

A
2×102C
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B
3×102C
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C
4×102C
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D
1×102C
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Solution

## The correct option is B 3×10−2C So given that Charge on A Q2 −1×10−2C Charge on B Q2=5×10−2 radius of A r1=1 cm radius of B r2=5 cm Let ′q′ charge gets transfered from A to B through the conducting wire. Charge on A =Q1−q Charge on B =Q2+q And now potential of both spheres become equal k(Q1−q)r1=k(Q2+q)r2 ⇒−1−q1=5+13⇒q=−2×10−2 Now charge on bigger sphere B is given by Q=Q2+q⇒Q=5−2=3 ×10−2=3×10−2 C  Suggest Corrections  0      Similar questions  Related Videos   PHYSICS
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