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Question

Two metallic wires P1 and P2 of the same material and same length but different cross - sectional areas A1 and A2 are joined together and then connected to a source of emf. find the ratio of the drift. Velocities of free electrons in the wires P1 and P2 if the wires are connected (i) in series, and (ii) in parallel.

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Solution

We know that,
I=neAvdvd=1neA
Let R1 and R2 be resistance of P1 and P2 and A1 and A2 are their cross sectional areas respectively.
R1=p1A1 and R2=p1A2
When connected in seried
vd1vd2=c(plA1+plA2)naA1c(plA1+plA2)neA2=A2A1
When,connected in parallel,
vd1vd2=εpl.1neA1A1εplA2.1neA2=1
1663474_1606607_ans_bf0d8353585340bfa9fd503626aa1ac2.png

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