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Question

Two mirrors meet at right angles. A ray of light is incident on one end at an angle of $$30^o$$ as shown in figure. Draw the reflected ray from the second mirror. 
464360_d93c4d981c89458f95028c0520254b7f.png


Solution

At Mirror OA,
Angle of incidence = angle of reflection = $$30^o$$
$$\angle{CAB} = 30^o$$

$$\angle{CAB}+\angle{CBA}+\angle{ACB}=180^o$$
$$30^o+90^o+\angle{ABC}=180^o$$
$$\angle{ABC} = 60^o$$

At mirror OB,
Angle of incidence = angle of reflection = $$60^o$$

Note that, 
$$AC\ ||\ OB$$
Angle between incident ray and AC = Angle between reflected ray and OB $$= 30^o$$
Hence, first incident ray are last reflected ray in this case are parallel.

487699_464360_ans_c99e9252c14f44a093263b37840796a5.png

Science
NCERT
Standard VIII

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