Question

# Two miscible fluids of densities 1.2 gm/cm3 and 1.4 gm/cm3 are mixed with a proportion of their volumes equal to 3: 5. Assuming both fluids to be perfectly miscible, what is the density of resulting liquid?

A

0.325 gm/cm3

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B

1.325 gm/cm3

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C

1.3 gm/cm3

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D

2.425 gm/cm3

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Solution

## The correct option is B. 1.325 gm/cm3Given : Density of liquid 1 = ρ1 = 1.2 gm/cm3 Density of liquid 2 = ρ2 = 1.4 gm/cm3 Let's say that the first liquid has a volume = v1=3v and the second liquid has a volume = v2=5v From above we can say that Liquid 1 has mass = m1=ρ1×3v and liquid 2 has mass = m2=ρ1×5v in the mixture. From definition, the density of the resulting liquid is given by,ρ=Total massTotal volume=m1+m2v1+v2 ⇒So, density of resulting mixture = ρ=(1.2×3)+(1.4×5)8 = ρ=1.325gm/cm3.

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